Department name using default dimension value in AX 2012

We can get the department name in different ways using default dimension value.

1st Way: Using Views.

static void DepartmentName(Args _args)
{
    DefaultDimensionView        defaultDimensionView;
    DimAttributeOMDepartment    dimAttributeOMDepartment;

   //DefaultDimension  =  5637151660
    select DisplayValue from defaultDimensionView
        where defaultDimensionView.DefaultDimension == 5637151660
            && defaultDimensionView.name == 'Department'
        join dimAttributeOMDepartment
            where dimAttributeOMDepartment.Value == defaultDimensionView.DisplayValue;

    info(dimAttributeOMDepartment.Name);
}

2nd Way: Using Tables.

static void getDepartmentName(Args _args)
{
str                                                       name;
DimensionAttributeValueSetItem      valueSetItem; 
DimensionAttribute                           dimAttribute; 
DimensionAttributeValue                 dimAttributeValue;

//Get the Department name for '5637151660' default dimension.
select DimensionAttributeValueSet from valueSetItem 
where valueSetItem.DimensionAttributeValueSet == 5637151660
            join RecId from dimAttributeValue 
                where valueSetItem.DimensionAttributeValue == dimAttributeValue.RecId 
            join RecId from dimAttribute 
                where dimAttributeValue.DimensionAttribute == dimAttribute.RecId 
                   && dimAttribute.Name == enum2str(sysdimension::Department);
       
         name = DimensionAttributeValue::find(dimAttributeValue.RecId).getName();
        
        info(name);
 }